Total Distance = 1.01 km = 1.01 × 1000 = 1010 m. Now, 101 plants will divide 1010 m in 100 equal parts each of length 1010/100 = 10.10 m. So five consecutive plants will have 4 such distances. So correct answer 4 × 10.1 = 40.4 m.
Row spacing should be 12-20 feet. Distance between plants in the shrub row should be 3-5 feet for deciduous species; if juniper is used for a shrub row, space plants 5-7 feet apart. For interior rows, space evergreens 8-12 feet apart and deciduous trees 10-14 feet apart.
LCM of 6, 9, 12, 15, 18 for a number above 1000 is 1080. Hence, option 3 is correct. Method 2: Check each of the given options by dividing by the given numbers such as 6, 9, 12, 15, 18 and leaves remainder 3.
A tree that grows up to 30 feet tall should be planted at least 3 feet from the edge of a concrete slab. 30- to 50-foot trees should be planted at least 5 to 6 feet away. Trees over 50 feet tall should be planted at least 7 to 8 feet from the sidewalk or driveway.
5 consecutive plants have 4 parts between them, So, the distance between 5 consecutive plants = 4 × 10.1 m = 40.4 m. Hence, the correct answer is an option(2) i.e., 40.4 m. -> UPSC Civil Services 2025 Exam Dates have been announced.
The easy way to determine spacing between different plants is to use the average of their mature sizes. As an example, when planting a 5-foot-wide hydrangea planted next to a boxwood that grows up to 3 feet wide, space the plants 4 feet apart. Remember to measure from the center of one plant to the next.
This means that when the product of these numbers is divided by 100, the remainder will be 0. So, the correct answer is (a) 0. UPSC PYQs Prelims & Mains with Solution, Past Paper PDF, CSAT Notes, Quotes, NCERT Books.
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